Base | Representation |
---|---|
bin | 1001001010100110011000… |
… | …10010101100010111111001 |
3 | 2122100211122110022222111221 |
4 | 10211103030102230113321 |
5 | 10120211241441131431 |
6 | 110511134103352041 |
7 | 4150115643202654 |
oct | 445231422542771 |
9 | 78324573288457 |
10 | 20155414005241 |
11 | 6470954834489 |
12 | 2316307452621 |
13 | b328553c7c98 |
14 | 4d9754a7c89b |
15 | 24e44ddea111 |
hex | 1254cc4ac5f9 |
20155414005241 has 2 divisors, whose sum is σ = 20155414005242. Its totient is φ = 20155414005240.
The previous prime is 20155414005193. The next prime is 20155414005271. The reversal of 20155414005241 is 14250041455102.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 15473799005625 + 4681614999616 = 3933675^2 + 2163704^2 .
It is a cyclic number.
It is not a de Polignac number, because 20155414005241 - 29 = 20155414004729 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 20155414005197 and 20155414005206.
It is not a weakly prime, because it can be changed into another prime (20155414005271) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10077707002620 + 10077707002621.
It is an arithmetic number, because the mean of its divisors is an integer number (10077707002621).
Almost surely, 220155414005241 is an apocalyptic number.
It is an amenable number.
20155414005241 is a deficient number, since it is larger than the sum of its proper divisors (1).
20155414005241 is an equidigital number, since it uses as much as digits as its factorization.
20155414005241 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 32000, while the sum is 34.
The spelling of 20155414005241 in words is "twenty trillion, one hundred fifty-five billion, four hundred fourteen million, five thousand, two hundred forty-one".
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