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20156540441 is a prime number
BaseRepresentation
bin10010110001011011…
…000110011000011001
31221000202002100100212
4102301123012120121
5312240033243231
613132040340505
71312332524012
oct226133063031
957022070325
1020156540441
118603929194
123aa6474735
131b92c5680b
14d92dd4009
157ce88d42b
hex4b16c6619

20156540441 has 2 divisors, whose sum is σ = 20156540442. Its totient is φ = 20156540440.

The previous prime is 20156540419. The next prime is 20156540479. The reversal of 20156540441 is 14404565102.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 15573792025 + 4582748416 = 124795^2 + 67696^2 .

It is a cyclic number.

It is not a de Polignac number, because 20156540441 - 218 = 20156278297 is a prime.

It is a super-2 number, since 2×201565404412 (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 20156540398 and 20156540407.

It is not a weakly prime, because it can be changed into another prime (20156543441) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10078270220 + 10078270221.

It is an arithmetic number, because the mean of its divisors is an integer number (10078270221).

Almost surely, 220156540441 is an apocalyptic number.

It is an amenable number.

20156540441 is a deficient number, since it is larger than the sum of its proper divisors (1).

20156540441 is an equidigital number, since it uses as much as digits as its factorization.

20156540441 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 19200, while the sum is 32.

It can be divided in two parts, 2015 and 6540441, that added together give a palindrome (6542456).

The spelling of 20156540441 in words is "twenty billion, one hundred fifty-six million, five hundred forty thousand, four hundred forty-one".