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201612564113 is a prime number
BaseRepresentation
bin1011101111000100001…
…0111001011010010001
3201021101201121102121012
42323301002321122101
511300400304022423
6232341452540305
720365101343052
oct2736102713221
9637351542535
10201612564113
117855a044514
12330a7781695
131602043391c
149a88326729
15539ed06078
hex2ef10b9691

201612564113 has 2 divisors, whose sum is σ = 201612564114. Its totient is φ = 201612564112.

The previous prime is 201612564091. The next prime is 201612564173. The reversal of 201612564113 is 311465216102.

201612564113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 110584846849 + 91027717264 = 332543^2 + 301708^2 .

It is a cyclic number.

It is not a de Polignac number, because 201612564113 - 28 = 201612563857 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 201612564113.

It is not a weakly prime, because it can be changed into another prime (201612564173) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100806282056 + 100806282057.

It is an arithmetic number, because the mean of its divisors is an integer number (100806282057).

Almost surely, 2201612564113 is an apocalyptic number.

It is an amenable number.

201612564113 is a deficient number, since it is larger than the sum of its proper divisors (1).

201612564113 is an equidigital number, since it uses as much as digits as its factorization.

201612564113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 8640, while the sum is 32.

The spelling of 201612564113 in words is "two hundred one billion, six hundred twelve million, five hundred sixty-four thousand, one hundred thirteen".