Base | Representation |
---|---|
bin | 1001001010110011110100… |
… | …01011011101101110110111 |
3 | 2122101112021002120011222211 |
4 | 10211121322023131232313 |
5 | 10120321024314010033 |
6 | 110514325504234251 |
7 | 4150462450620466 |
oct | 445317213355667 |
9 | 78345232504884 |
10 | 20162626313143 |
11 | 6473a15a08126 |
12 | 231779a90b987 |
13 | b334346a73b2 |
14 | 4d9c3a8a29dd |
15 | 24e7221a02cd |
hex | 12567a2ddbb7 |
20162626313143 has 2 divisors, whose sum is σ = 20162626313144. Its totient is φ = 20162626313142.
The previous prime is 20162626313117. The next prime is 20162626313329. The reversal of 20162626313143 is 34131362626102.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 20162626313143 - 221 = 20162624215991 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 20162626313096 and 20162626313105.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (20162626313443) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10081313156571 + 10081313156572.
It is an arithmetic number, because the mean of its divisors is an integer number (10081313156572).
Almost surely, 220162626313143 is an apocalyptic number.
20162626313143 is a deficient number, since it is larger than the sum of its proper divisors (1).
20162626313143 is an equidigital number, since it uses as much as digits as its factorization.
20162626313143 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 186624, while the sum is 40.
Adding to 20162626313143 its reverse (34131362626102), we get a palindrome (54293988939245).
The spelling of 20162626313143 in words is "twenty trillion, one hundred sixty-two billion, six hundred twenty-six million, three hundred thirteen thousand, one hundred forty-three".
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