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20162626313143 is a prime number
BaseRepresentation
bin1001001010110011110100…
…01011011101101110110111
32122101112021002120011222211
410211121322023131232313
510120321024314010033
6110514325504234251
74150462450620466
oct445317213355667
978345232504884
1020162626313143
116473a15a08126
12231779a90b987
13b334346a73b2
144d9c3a8a29dd
1524e7221a02cd
hex12567a2ddbb7

20162626313143 has 2 divisors, whose sum is σ = 20162626313144. Its totient is φ = 20162626313142.

The previous prime is 20162626313117. The next prime is 20162626313329. The reversal of 20162626313143 is 34131362626102.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 20162626313143 - 221 = 20162624215991 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 20162626313096 and 20162626313105.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (20162626313443) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10081313156571 + 10081313156572.

It is an arithmetic number, because the mean of its divisors is an integer number (10081313156572).

Almost surely, 220162626313143 is an apocalyptic number.

20162626313143 is a deficient number, since it is larger than the sum of its proper divisors (1).

20162626313143 is an equidigital number, since it uses as much as digits as its factorization.

20162626313143 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 186624, while the sum is 40.

Adding to 20162626313143 its reverse (34131362626102), we get a palindrome (54293988939245).

The spelling of 20162626313143 in words is "twenty trillion, one hundred sixty-two billion, six hundred twenty-six million, three hundred thirteen thousand, one hundred forty-three".