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201696251693813 is a prime number
BaseRepresentation
bin101101110111000100010001…
…011011110100101011110101
3222110010222021120110012100022
4231313010101123310223311
5202414042410413200223
61552545551234054525
760325034066651642
oct5567042133645365
9873128246405308
10201696251693813
11592a2999963a28
121a75610271a445
138870b4b2895a6
1437b4217618dc9
15184b8b07a3ac8
hexb771116f4af5

201696251693813 has 2 divisors, whose sum is σ = 201696251693814. Its totient is φ = 201696251693812.

The previous prime is 201696251693791. The next prime is 201696251693843. The reversal of 201696251693813 is 318396152696102.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 147528668315044 + 54167583378769 = 12146138^2 + 7359863^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-201696251693813 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (201696251693843) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100848125846906 + 100848125846907.

It is an arithmetic number, because the mean of its divisors is an integer number (100848125846907).

Almost surely, 2201696251693813 is an apocalyptic number.

It is an amenable number.

201696251693813 is a deficient number, since it is larger than the sum of its proper divisors (1).

201696251693813 is an equidigital number, since it uses as much as digits as its factorization.

201696251693813 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 25194240, while the sum is 62.

The spelling of 201696251693813 in words is "two hundred one trillion, six hundred ninety-six billion, two hundred fifty-one million, six hundred ninety-three thousand, eight hundred thirteen".