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201711317 is a prime number
BaseRepresentation
bin11000000010111…
…01111011010101
3112001112222220112
430001131323111
5403114230232
632003212405
74666342433
oct1401357325
9461488815
10201711317
11a3951775
1257677105
1332a36212
141cb09d53
1512a964b2
hexc05ded5

201711317 has 2 divisors, whose sum is σ = 201711318. Its totient is φ = 201711316.

The previous prime is 201711299. The next prime is 201711343. The reversal of 201711317 is 713117102.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 166771396 + 34939921 = 12914^2 + 5911^2 .

It is a cyclic number.

It is not a de Polignac number, because 201711317 - 28 = 201711061 is a prime.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 201711292 and 201711301.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (201711347) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100855658 + 100855659.

It is an arithmetic number, because the mean of its divisors is an integer number (100855659).

Almost surely, 2201711317 is an apocalyptic number.

It is an amenable number.

201711317 is a deficient number, since it is larger than the sum of its proper divisors (1).

201711317 is an equidigital number, since it uses as much as digits as its factorization.

201711317 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 294, while the sum is 23.

The square root of 201711317 is about 14202.5109399711. The cubic root of 201711317 is about 586.4667864975.

Adding to 201711317 its reverse (713117102), we get a palindrome (914828419).

The spelling of 201711317 in words is "two hundred one million, seven hundred eleven thousand, three hundred seventeen".