Base | Representation |
---|---|
bin | 11101010110101000110… |
… | …100101010101100001101 |
3 | 21010211200012001220000122 |
4 | 131112220310222230031 |
5 | 231022132020243321 |
6 | 4142402005234325 |
7 | 265510255303664 |
oct | 35265064525415 |
9 | 7124605056018 |
10 | 2017172040461 |
11 | 708529035a66 |
12 | 286b36a029a5 |
13 | 1182ac0a2766 |
14 | 6d8bb353ddb |
15 | 377108398ab |
hex | 1d5a8d2ab0d |
2017172040461 has 2 divisors, whose sum is σ = 2017172040462. Its totient is φ = 2017172040460.
The previous prime is 2017172040383. The next prime is 2017172040469. The reversal of 2017172040461 is 1640402717102.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1509666829225 + 507505211236 = 1228685^2 + 712394^2 .
It is a cyclic number.
It is not a de Polignac number, because 2017172040461 - 222 = 2017167846157 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2017172040469) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1008586020230 + 1008586020231.
It is an arithmetic number, because the mean of its divisors is an integer number (1008586020231).
Almost surely, 22017172040461 is an apocalyptic number.
It is an amenable number.
2017172040461 is a deficient number, since it is larger than the sum of its proper divisors (1).
2017172040461 is an equidigital number, since it uses as much as digits as its factorization.
2017172040461 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 18816, while the sum is 35.
Adding to 2017172040461 its reverse (1640402717102), we get a palindrome (3657574757563).
The spelling of 2017172040461 in words is "two trillion, seventeen billion, one hundred seventy-two million, forty thousand, four hundred sixty-one".
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