Base | Representation |
---|---|
bin | 1001001011001010001011… |
… | …10110111010101000100001 |
3 | 2122102200020220001001201121 |
4 | 10211211011312322220201 |
5 | 10121020122123210103 |
6 | 110524033150132241 |
7 | 4151366136365122 |
oct | 445450566725041 |
9 | 78380226031647 |
10 | 20174633413153 |
11 | 647901767907a |
12 | 2319b8bab1081 |
13 | b345c91567bb |
14 | 4da65940c049 |
15 | 24ebc63746bd |
hex | 125945dbaa21 |
20174633413153 has 2 divisors, whose sum is σ = 20174633413154. Its totient is φ = 20174633413152.
The previous prime is 20174633413147. The next prime is 20174633413159. The reversal of 20174633413153 is 35131433647102.
It is a balanced prime because it is at equal distance from previous prime (20174633413147) and next prime (20174633413159).
It can be written as a sum of positive squares in only one way, i.e., 16810721607744 + 3363911805409 = 4100088^2 + 1834097^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-20174633413153 is a prime.
It is not a weakly prime, because it can be changed into another prime (20174633413159) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10087316706576 + 10087316706577.
It is an arithmetic number, because the mean of its divisors is an integer number (10087316706577).
Almost surely, 220174633413153 is an apocalyptic number.
It is an amenable number.
20174633413153 is a deficient number, since it is larger than the sum of its proper divisors (1).
20174633413153 is an equidigital number, since it uses as much as digits as its factorization.
20174633413153 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 544320, while the sum is 43.
The spelling of 20174633413153 in words is "twenty trillion, one hundred seventy-four billion, six hundred thirty-three million, four hundred thirteen thousand, one hundred fifty-three".
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