Base | Representation |
---|---|
bin | 10010110010100110… |
… | …010011100010110001 |
3 | 1221002010011221212101 |
4 | 102302212103202301 |
5 | 312310110131103 |
6 | 13134023100401 |
7 | 1312662224215 |
oct | 226246234261 |
9 | 57063157771 |
10 | 20176255153 |
11 | 8613a7413a |
12 | 3ab0ba1701 |
13 | 1b9706a122 |
14 | d95886945 |
15 | 7d1484a1d |
hex | 4b29938b1 |
20176255153 has 2 divisors, whose sum is σ = 20176255154. Its totient is φ = 20176255152.
The previous prime is 20176255147. The next prime is 20176255159. The reversal of 20176255153 is 35155267102.
It is a balanced prime because it is at equal distance from previous prime (20176255147) and next prime (20176255159).
It can be written as a sum of positive squares in only one way, i.e., 17653905424 + 2522349729 = 132868^2 + 50223^2 .
It is a cyclic number.
It is not a de Polignac number, because 20176255153 - 221 = 20174158001 is a prime.
It is not a weakly prime, because it can be changed into another prime (20176255159) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10088127576 + 10088127577.
It is an arithmetic number, because the mean of its divisors is an integer number (10088127577).
Almost surely, 220176255153 is an apocalyptic number.
It is an amenable number.
20176255153 is a deficient number, since it is larger than the sum of its proper divisors (1).
20176255153 is an equidigital number, since it uses as much as digits as its factorization.
20176255153 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 63000, while the sum is 37.
The spelling of 20176255153 in words is "twenty billion, one hundred seventy-six million, two hundred fifty-five thousand, one hundred fifty-three".
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