Base | Representation |
---|---|
bin | 10010110011000111… |
… | …101101101110101001 |
3 | 1221002201122220121001 |
4 | 102303013231232221 |
5 | 312314330410121 |
6 | 13134534515001 |
7 | 1313126531605 |
oct | 226307555651 |
9 | 57081586531 |
10 | 20185013161 |
11 | 8618a06165 |
12 | 3ab3b05a61 |
13 | 1b98b15591 |
14 | d96ac6505 |
15 | 7d2114991 |
hex | 4b31edba9 |
20185013161 has 2 divisors, whose sum is σ = 20185013162. Its totient is φ = 20185013160.
The previous prime is 20185013159. The next prime is 20185013179. The reversal of 20185013161 is 16131058102.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 16814049561 + 3370963600 = 129669^2 + 58060^2 .
It is a cyclic number.
It is not a de Polignac number, because 20185013161 - 21 = 20185013159 is a prime.
Together with 20185013159, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (20185013111) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10092506580 + 10092506581.
It is an arithmetic number, because the mean of its divisors is an integer number (10092506581).
Almost surely, 220185013161 is an apocalyptic number.
It is an amenable number.
20185013161 is a deficient number, since it is larger than the sum of its proper divisors (1).
20185013161 is an equidigital number, since it uses as much as digits as its factorization.
20185013161 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1440, while the sum is 28.
The spelling of 20185013161 in words is "twenty billion, one hundred eighty-five million, thirteen thousand, one hundred sixty-one".
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