Base | Representation |
---|---|
bin | 101101111001110111101111… |
… | …001000100101000011001011 |
3 | 222110211101200000211210202202 |
4 | 231321313233020211003023 |
5 | 202430222032114031021 |
6 | 1553214300402150415 |
7 | 60344665244301614 |
oct | 5571675710450313 |
9 | 873741600753682 |
10 | 201888949752011 |
11 | 593676939a0185 |
12 | 1a78752095240b |
13 | 888607a874c32 |
14 | 37bd697a22c0b |
15 | 18518dcb69a0b |
hex | b79def2250cb |
201888949752011 has 2 divisors, whose sum is σ = 201888949752012. Its totient is φ = 201888949752010.
The previous prime is 201888949751933. The next prime is 201888949752013. The reversal of 201888949752011 is 110257949888102.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-201888949752011 is a prime.
Together with 201888949752013, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (201888949752013) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100944474876005 + 100944474876006.
It is an arithmetic number, because the mean of its divisors is an integer number (100944474876006).
Almost surely, 2201888949752011 is an apocalyptic number.
201888949752011 is a deficient number, since it is larger than the sum of its proper divisors (1).
201888949752011 is an equidigital number, since it uses as much as digits as its factorization.
201888949752011 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 23224320, while the sum is 65.
The spelling of 201888949752011 in words is "two hundred one trillion, eight hundred eighty-eight billion, nine hundred forty-nine million, seven hundred fifty-two thousand, eleven".
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