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20201241202013 is a prime number
BaseRepresentation
bin1001001011111011101111…
…10011100100110101011101
32122112012221020021210020002
410211331313303210311131
510121434120221431023
6110544153323304045
74153330406016434
oct445756763446535
978465836253202
1020201241202013
116489331016723
12232317697b025
13b36c797c2071
144dba6111611b
15250732283b28
hex125f77ce4d5d

20201241202013 has 2 divisors, whose sum is σ = 20201241202014. Its totient is φ = 20201241202012.

The previous prime is 20201241201979. The next prime is 20201241202057. The reversal of 20201241202013 is 31020214210202.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 19911567968644 + 289673233369 = 4462238^2 + 538213^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-20201241202013 is a prime.

It is a super-2 number, since 2×202012412020132 (a number of 27 digits) contains 22 as substring.

It is a Sophie Germain prime.

It is a Curzon number.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (20201241202613) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10100620601006 + 10100620601007.

It is an arithmetic number, because the mean of its divisors is an integer number (10100620601007).

Almost surely, 220201241202013 is an apocalyptic number.

It is an amenable number.

20201241202013 is a deficient number, since it is larger than the sum of its proper divisors (1).

20201241202013 is an equidigital number, since it uses as much as digits as its factorization.

20201241202013 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 384, while the sum is 20.

Adding to 20201241202013 its reverse (31020214210202), we get a palindrome (51221455412215).

The spelling of 20201241202013 in words is "twenty trillion, two hundred one billion, two hundred forty-one million, two hundred two thousand, thirteen".