Base | Representation |
---|---|
bin | 11101011001011000110… |
… | …010101011111100011101 |
3 | 21011010021221021210021222 |
4 | 131121120302223330131 |
5 | 231044203310430300 |
6 | 4144010550503125 |
7 | 265643364220451 |
oct | 35313062537435 |
9 | 7133257253258 |
10 | 2020124311325 |
11 | 70980356683a |
12 | 28761b664aa5 |
13 | 11865c9153b3 |
14 | 6dabb494661 |
15 | 37834b01785 |
hex | 1d658cabf1d |
2020124311325 has 24 divisors (see below), whose sum is σ = 2650599160320. Its totient is φ = 1523025590400.
The previous prime is 2020124311277. The next prime is 2020124311333. The reversal of 2020124311325 is 5231134210202.
It is not a de Polignac number, because 2020124311325 - 210 = 2020124310301 is a prime.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 2020124311294 and 2020124311303.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 11042504 + ... + 11223953.
It is an arithmetic number, because the mean of its divisors is an integer number (110441631680).
Almost surely, 22020124311325 is an apocalyptic number.
2020124311325 is a gapful number since it is divisible by the number (25) formed by its first and last digit.
It is an amenable number.
2020124311325 is a deficient number, since it is larger than the sum of its proper divisors (630474848995).
2020124311325 is a wasteful number, since it uses less digits than its factorization.
2020124311325 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 22266677 (or 22266672 counting only the distinct ones).
The product of its (nonzero) digits is 2880, while the sum is 26.
Adding to 2020124311325 its reverse (5231134210202), we get a palindrome (7251258521527).
The spelling of 2020124311325 in words is "two trillion, twenty billion, one hundred twenty-four million, three hundred eleven thousand, three hundred twenty-five".
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