Base | Representation |
---|---|
bin | 10010110100001111… |
… | …111001011100110111 |
3 | 1221011001021021020000 |
4 | 102310033321130313 |
5 | 312334201414133 |
6 | 13140452242343 |
7 | 1313446422111 |
oct | 226417713467 |
9 | 57131237200 |
10 | 20203935543 |
11 | 862865a8a0 |
12 | 3aba3103b3 |
13 | 1b9ca0c35c |
14 | d994103b1 |
15 | 7d3b01413 |
hex | 4b43f9737 |
20203935543 has 80 divisors (see below), whose sum is σ = 34263668736. Its totient is φ = 11756871360.
The previous prime is 20203935541. The next prime is 20203935571. The reversal of 20203935543 is 34553930202.
20203935543 is a `hidden beast` number, since 2 + 0 + 20 + 3 + 93 + 5 + 543 = 666.
It is not a de Polignac number, because 20203935543 - 21 = 20203935541 is a prime.
It is a super-3 number, since 3×202039355433 (a number of 32 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a junction number, because it is equal to n+sod(n) for n = 20203935498 and 20203935507.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (20203935541) by changing a digit.
It is a polite number, since it can be written in 79 ways as a sum of consecutive naturals, for example, 2214930 + ... + 2224032.
Almost surely, 220203935543 is an apocalyptic number.
20203935543 is a deficient number, since it is larger than the sum of its proper divisors (14059733193).
20203935543 is a wasteful number, since it uses less digits than its factorization.
20203935543 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 9226 (or 9217 counting only the distinct ones).
The product of its (nonzero) digits is 97200, while the sum is 36.
The spelling of 20203935543 in words is "twenty billion, two hundred three million, nine hundred thirty-five thousand, five hundred forty-three".
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