Base | Representation |
---|---|
bin | 101101111100111100010010… |
… | …101101011000100010010011 |
3 | 222111120120102111010020222122 |
4 | 231330330102231120202103 |
5 | 202442201300000001042 |
6 | 1553455242553324455 |
7 | 60366146254641524 |
oct | 5574742255304223 |
9 | 874516374106878 |
10 | 202100000000147 |
11 | 5943914629a357 |
12 | 1a80040110672b |
13 | 889cc43332a72 |
14 | 37c999953484b |
15 | 18571412a67d2 |
hex | b7cf12b58893 |
202100000000147 has 2 divisors, whose sum is σ = 202100000000148. Its totient is φ = 202100000000146.
The previous prime is 202100000000081. The next prime is 202100000000207. The reversal of 202100000000147 is 741000000001202.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 202100000000147 - 222 = 202099995805843 is a prime.
It is not a weakly prime, because it can be changed into another prime (202100000000447) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 101050000000073 + 101050000000074.
It is an arithmetic number, because the mean of its divisors is an integer number (101050000000074).
Almost surely, 2202100000000147 is an apocalyptic number.
202100000000147 is a deficient number, since it is larger than the sum of its proper divisors (1).
202100000000147 is an equidigital number, since it uses as much as digits as its factorization.
202100000000147 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 112, while the sum is 17.
Adding to 202100000000147 its reverse (741000000001202), we get a palindrome (943100000001349).
The spelling of 202100000000147 in words is "two hundred two trillion, one hundred billion, one hundred forty-seven", and thus it is an aban number.
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