Base | Representation |
---|---|
bin | 101101111100111101010101… |
… | …100101100011011100001011 |
3 | 222111120200022200101211102101 |
4 | 231330331111211203130023 |
5 | 202442211044214134011 |
6 | 1553455550154214231 |
7 | 60366216130651654 |
oct | 5574752545433413 |
9 | 874520280354371 |
10 | 202101122021131 |
11 | 59439671685323 |
12 | 1a800674a24377 |
13 | 88a00919239c8 |
14 | 37c9a6456652b |
15 | 18571a9a3c2c1 |
hex | b7cf5596370b |
202101122021131 has 2 divisors, whose sum is σ = 202101122021132. Its totient is φ = 202101122021130.
The previous prime is 202101122021027. The next prime is 202101122021159. The reversal of 202101122021131 is 131120221101202.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 202101122021131 - 213 = 202101122012939 is a prime.
It is a super-2 number, since 2×2021011220211312 (a number of 29 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 202101122021099 and 202101122021108.
It is not a weakly prime, because it can be changed into another prime (202101122021731) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 101050561010565 + 101050561010566.
It is an arithmetic number, because the mean of its divisors is an integer number (101050561010566).
Almost surely, 2202101122021131 is an apocalyptic number.
202101122021131 is a deficient number, since it is larger than the sum of its proper divisors (1).
202101122021131 is an equidigital number, since it uses as much as digits as its factorization.
202101122021131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 96, while the sum is 19.
Adding to 202101122021131 its reverse (131120221101202), we get a palindrome (333221343122333).
The spelling of 202101122021131 in words is "two hundred two trillion, one hundred one billion, one hundred twenty-two million, twenty-one thousand, one hundred thirty-one".
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