Base | Representation |
---|---|
bin | 10010110100101000… |
… | …100110101001110111 |
3 | 1221011111110022110101 |
4 | 102310220212221313 |
5 | 312342331142101 |
6 | 13141243134531 |
7 | 1313555445256 |
oct | 226450465167 |
9 | 57144408411 |
10 | 20210412151 |
11 | 8631283866 |
12 | 3b00514447 |
13 | 1ba1169277 |
14 | d9a21879d |
15 | 7d4480401 |
hex | 4b4a26a77 |
20210412151 has 2 divisors, whose sum is σ = 20210412152. Its totient is φ = 20210412150.
The previous prime is 20210412137. The next prime is 20210412161. The reversal of 20210412151 is 15121401202.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 20210412151 - 215 = 20210379383 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (20210412161) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10105206075 + 10105206076.
It is an arithmetic number, because the mean of its divisors is an integer number (10105206076).
Almost surely, 220210412151 is an apocalyptic number.
20210412151 is a deficient number, since it is larger than the sum of its proper divisors (1).
20210412151 is an equidigital number, since it uses as much as digits as its factorization.
20210412151 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 160, while the sum is 19.
Adding to 20210412151 its reverse (15121401202), we get a palindrome (35331813353).
The spelling of 20210412151 in words is "twenty billion, two hundred ten million, four hundred twelve thousand, one hundred fifty-one".
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