202104125231 has 2 divisors, whose sum is σ = 202104125232. Its totient is φ = 202104125230.

The previous prime is 202104125203. The next prime is 202104125239. The reversal of 202104125231 is 132521401202.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 202104125231 - 2¹⁰ = 202104124207 is a prime.

It is a super-3 number, since 3×202104125231³ (a number of 35 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a junction number, because it is equal to n+sod(n) for n = 202104125197 and 202104125206.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (202104125239) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 101052062615 + 101052062616.

It is an arithmetic number, because the mean of its divisors is an integer number (101052062616).

Almost surely, 2^202104125231 is an apocalyptic number.

202104125231 is a deficient number, since it is larger than the sum of its proper divisors (1).

202104125231 is an equidigital number, since it uses as much as digits as its factorization.

202104125231 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 960, while the sum is 23.

Adding to 202104125231 its reverse (132521401202), we get a palindrome (334625526433).

The spelling of 202104125231 in words is "two hundred two billion, one hundred four million, one hundred twenty-five thousand, two hundred thirty-one".