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2021120200241 is a prime number
BaseRepresentation
bin11101011010010100001…
…001101100111000110001
321011012212100020012001122
4131122110021230320301
5231103223232401431
64144253444112025
7266010146146622
oct35322411547061
97135770205048
102021120200241
1170a17473192a
12287859095615
1311878b04328c
146db73851a49
153789226ea7b
hex1d69426ce31

2021120200241 has 2 divisors, whose sum is σ = 2021120200242. Its totient is φ = 2021120200240.

The previous prime is 2021120200219. The next prime is 2021120200243. The reversal of 2021120200241 is 1420020211202.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1754989057600 + 266131142641 = 1324760^2 + 515879^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2021120200241 is a prime.

Together with 2021120200243, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (2021120200243) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1010560100120 + 1010560100121.

It is an arithmetic number, because the mean of its divisors is an integer number (1010560100121).

Almost surely, 22021120200241 is an apocalyptic number.

It is an amenable number.

2021120200241 is a deficient number, since it is larger than the sum of its proper divisors (1).

2021120200241 is an equidigital number, since it uses as much as digits as its factorization.

2021120200241 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 128, while the sum is 17.

Adding to 2021120200241 its reverse (1420020211202), we get a palindrome (3441140411443).

The spelling of 2021120200241 in words is "two trillion, twenty-one billion, one hundred twenty million, two hundred thousand, two hundred forty-one".