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202112121193 is a prime number
BaseRepresentation
bin1011110000111011010…
…0100011100101101001
3201022200112121120002021
42330032310203211221
511302411200334233
6232503220104441
720413345453513
oct2741664434551
9638615546067
10202112121193
1178796029104
1233206b35121
131609ca92228
149ad4804bb3
1553cdad2e2d
hex2f0ed23969

202112121193 has 2 divisors, whose sum is σ = 202112121194. Its totient is φ = 202112121192.

The previous prime is 202112121149. The next prime is 202112121217. The reversal of 202112121193 is 391121211202.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 120834102544 + 81278018649 = 347612^2 + 285093^2 .

It is a cyclic number.

It is not a de Polignac number, because 202112121193 - 213 = 202112113001 is a prime.

It is a super-3 number, since 3×2021121211933 (a number of 35 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (202112221193) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 101056060596 + 101056060597.

It is an arithmetic number, because the mean of its divisors is an integer number (101056060597).

Almost surely, 2202112121193 is an apocalyptic number.

It is an amenable number.

202112121193 is a deficient number, since it is larger than the sum of its proper divisors (1).

202112121193 is an equidigital number, since it uses as much as digits as its factorization.

202112121193 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 432, while the sum is 25.

Adding to 202112121193 its reverse (391121211202), we get a palindrome (593233332395).

The spelling of 202112121193 in words is "two hundred two billion, one hundred twelve million, one hundred twenty-one thousand, one hundred ninety-three".