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202112132147 is a prime number
BaseRepresentation
bin1011110000111011010…
…0100110010000110011
3201022200112122010002222
42330032310212100303
511302411201212042
6232503220231255
720413345530452
oct2741664462063
9638615563088
10202112132147
1178796036362
1233206b3b52b
131609ca97203
149ad4808b99
1553cdad62d2
hex2f0ed26433

202112132147 has 2 divisors, whose sum is σ = 202112132148. Its totient is φ = 202112132146.

The previous prime is 202112132087. The next prime is 202112132177. The reversal of 202112132147 is 741231211202.

It is a happy number.

202112132147 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 202112132147 - 226 = 202045023283 is a prime.

It is a super-2 number, since 2×2021121321472 (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (202112132177) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 101056066073 + 101056066074.

It is an arithmetic number, because the mean of its divisors is an integer number (101056066074).

Almost surely, 2202112132147 is an apocalyptic number.

202112132147 is a deficient number, since it is larger than the sum of its proper divisors (1).

202112132147 is an equidigital number, since it uses as much as digits as its factorization.

202112132147 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1344, while the sum is 26.

Adding to 202112132147 its reverse (741231211202), we get a palindrome (943343343349).

The spelling of 202112132147 in words is "two hundred two billion, one hundred twelve million, one hundred thirty-two thousand, one hundred forty-seven".