Base | Representation |
---|---|
bin | 11101011010010101011… |
… | …100111010010001001001 |
3 | 21011012220212021101112122 |
4 | 131122111130322101021 |
5 | 231103244323404001 |
6 | 4144255543421025 |
7 | 266010532435646 |
oct | 35322534722111 |
9 | 7135825241478 |
10 | 2021142013001 |
11 | 70a185a80101 |
12 | 287864454775 |
13 | 11879270c837 |
14 | 6db766ccdcd |
15 | 3789412cb1b |
hex | 1d69573a449 |
2021142013001 has 2 divisors, whose sum is σ = 2021142013002. Its totient is φ = 2021142013000.
The previous prime is 2021142012947. The next prime is 2021142013049. The reversal of 2021142013001 is 1003102411202.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1792706766400 + 228435246601 = 1338920^2 + 477949^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2021142013001 is a prime.
It is not a weakly prime, because it can be changed into another prime (2021142013061) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1010571006500 + 1010571006501.
It is an arithmetic number, because the mean of its divisors is an integer number (1010571006501).
Almost surely, 22021142013001 is an apocalyptic number.
It is an amenable number.
2021142013001 is a deficient number, since it is larger than the sum of its proper divisors (1).
2021142013001 is an equidigital number, since it uses as much as digits as its factorization.
2021142013001 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 96, while the sum is 17.
Adding to 2021142013001 its reverse (1003102411202), we get a palindrome (3024244424203).
The spelling of 2021142013001 in words is "two trillion, twenty-one billion, one hundred forty-two million, thirteen thousand, one".
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