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20214013 is a prime number
BaseRepresentation
bin100110100011…
…1000011111101
31102000222102011
41031013003331
520133322023
62001131221
7333546661
oct115070375
942028364
1020214013
11104570a6
126929b11
134259971
1429828a1
151b9450d
hex13470fd

20214013 has 2 divisors, whose sum is σ = 20214014. Its totient is φ = 20214012.

The previous prime is 20214001. The next prime is 20214017. The reversal of 20214013 is 31041202.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 17530969 + 2683044 = 4187^2 + 1638^2 .

It is a cyclic number.

It is not a de Polignac number, because 20214013 - 25 = 20213981 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 20213984 and 20214002.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (20214017) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10107006 + 10107007.

It is an arithmetic number, because the mean of its divisors is an integer number (10107007).

Almost surely, 220214013 is an apocalyptic number.

It is an amenable number.

20214013 is a deficient number, since it is larger than the sum of its proper divisors (1).

20214013 is an equidigital number, since it uses as much as digits as its factorization.

20214013 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 48, while the sum is 13.

The square root of 20214013 is about 4495.9996663701. Note that the first 3 decimals coincide. The cubic root of 20214013 is about 272.4065296796.

Adding to 20214013 its reverse (31041202), we get a palindrome (51255215).

The spelling of 20214013 in words is "twenty million, two hundred fourteen thousand, thirteen".