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20214113141401 is a prime number
BaseRepresentation
bin1001001100010011101110…
…00010001000001010011001
32122120110011022010001112221
410212021313002020022121
510122142000431011101
6110554122501504041
74154264365501504
oct446116702101231
978513138101487
1020214113141401
116493836984263
122325769712021
13b3824b4a6c4a
144dc52286813b
15250c3733baa1
hex126277088299

20214113141401 has 2 divisors, whose sum is σ = 20214113141402. Its totient is φ = 20214113141400.

The previous prime is 20214113141357. The next prime is 20214113141413. The reversal of 20214113141401 is 10414131141202.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 17004497569801 + 3209615571600 = 4123651^2 + 1791540^2 .

It is a cyclic number.

It is not a de Polignac number, because 20214113141401 - 27 = 20214113141273 is a prime.

It is a super-2 number, since 2×202141131414012 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (20214113141441) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10107056570700 + 10107056570701.

It is an arithmetic number, because the mean of its divisors is an integer number (10107056570701).

Almost surely, 220214113141401 is an apocalyptic number.

It is an amenable number.

20214113141401 is a deficient number, since it is larger than the sum of its proper divisors (1).

20214113141401 is an equidigital number, since it uses as much as digits as its factorization.

20214113141401 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 768, while the sum is 25.

Adding to 20214113141401 its reverse (10414131141202), we get a palindrome (30628244282603).

The spelling of 20214113141401 in words is "twenty trillion, two hundred fourteen billion, one hundred thirteen million, one hundred forty-one thousand, four hundred one".