Base | Representation |
---|---|
bin | 1011110001000010111… |
… | …1011101110100100001 |
3 | 201022202210020111201212 |
4 | 2330100233131310201 |
5 | 11302442422410111 |
6 | 232510330435505 |
7 | 20414216356601 |
oct | 2742057356441 |
9 | 638683214655 |
10 | 202144341281 |
11 | 78802235583 |
12 | 33215892b95 |
13 | 160a666387c |
14 | 9ad8bd0c01 |
15 | 53d184998b |
hex | 2f10bddd21 |
202144341281 has 2 divisors, whose sum is σ = 202144341282. Its totient is φ = 202144341280.
The previous prime is 202144341241. The next prime is 202144341331. The reversal of 202144341281 is 182143441202.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 174215246881 + 27929094400 = 417391^2 + 167120^2 .
It is a cyclic number.
It is not a de Polignac number, because 202144341281 - 234 = 184964472097 is a prime.
It is a super-2 number, since 2×2021443412812 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (202144341241) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 101072170640 + 101072170641.
It is an arithmetic number, because the mean of its divisors is an integer number (101072170641).
Almost surely, 2202144341281 is an apocalyptic number.
It is an amenable number.
202144341281 is a deficient number, since it is larger than the sum of its proper divisors (1).
202144341281 is an equidigital number, since it uses as much as digits as its factorization.
202144341281 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 12288, while the sum is 32.
Adding to 202144341281 its reverse (182143441202), we get a palindrome (384287782483).
The spelling of 202144341281 in words is "two hundred two billion, one hundred forty-four million, three hundred forty-one thousand, two hundred eighty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.067 sec. • engine limits •