Base | Representation |
---|---|
bin | 11101011011001110100… |
… | …011110000111011101001 |
3 | 21011022101122002211000201 |
4 | 131123032203300323221 |
5 | 231112230112023311 |
6 | 4144535011032201 |
7 | 266043345230551 |
oct | 35331643607351 |
9 | 7138348084021 |
10 | 2022100111081 |
11 | 70a6278843a6 |
12 | 287a9129b661 |
13 | 1188b606858b |
14 | 6dc27a50161 |
15 | 378ed2d39c1 |
hex | 1d6ce8f0ee9 |
2022100111081 has 2 divisors, whose sum is σ = 2022100111082. Its totient is φ = 2022100111080.
The previous prime is 2022100111051. The next prime is 2022100111121. The reversal of 2022100111081 is 1801110012202.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1875365913600 + 146734197481 = 1369440^2 + 383059^2 .
It is a cyclic number.
It is not a de Polignac number, because 2022100111081 - 25 = 2022100111049 is a prime.
It is a super-3 number, since 3×20221001110813 (a number of 38 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not a weakly prime, because it can be changed into another prime (2022100111051) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1011050055540 + 1011050055541.
It is an arithmetic number, because the mean of its divisors is an integer number (1011050055541).
Almost surely, 22022100111081 is an apocalyptic number.
It is an amenable number.
2022100111081 is a deficient number, since it is larger than the sum of its proper divisors (1).
2022100111081 is an equidigital number, since it uses as much as digits as its factorization.
2022100111081 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 64, while the sum is 19.
Adding to 2022100111081 its reverse (1801110012202), we get a palindrome (3823210123283).
The spelling of 2022100111081 in words is "two trillion, twenty-two billion, one hundred million, one hundred eleven thousand, eighty-one".
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