Base | Representation |
---|---|
bin | 101101111110100010101111… |
… | …111100010100110000011111 |
3 | 222111222002101102100002121112 |
4 | 231332202233330110300133 |
5 | 203001002101100402033 |
6 | 1554021555215052235 |
7 | 60410122414360214 |
oct | 5576425774246037 |
9 | 874862342302545 |
10 | 202210012122143 |
11 | 5948086a269943 |
12 | 1a8197a3b1107b |
13 | 88aa4261b533c |
14 | 37d1034191b0b |
15 | 1859e2e495c48 |
hex | b7e8aff14c1f |
202210012122143 has 2 divisors, whose sum is σ = 202210012122144. Its totient is φ = 202210012122142.
The previous prime is 202210012122091. The next prime is 202210012122163. The reversal of 202210012122143 is 341221210012202.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-202210012122143 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (202210012122163) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 101105006061071 + 101105006061072.
It is an arithmetic number, because the mean of its divisors is an integer number (101105006061072).
Almost surely, 2202210012122143 is an apocalyptic number.
202210012122143 is a deficient number, since it is larger than the sum of its proper divisors (1).
202210012122143 is an equidigital number, since it uses as much as digits as its factorization.
202210012122143 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 768, while the sum is 23.
Adding to 202210012122143 its reverse (341221210012202), we get a palindrome (543431222134345).
The spelling of 202210012122143 in words is "two hundred two trillion, two hundred ten billion, twelve million, one hundred twenty-two thousand, one hundred forty-three".
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