Base | Representation |
---|---|
bin | 1001001100100000101111… |
… | …00000001001001111001111 |
3 | 2122121010012020202010010022 |
4 | 10212100113200021033033 |
5 | 10122300303141110413 |
6 | 111001240101332355 |
7 | 4154632500600515 |
oct | 446202740111717 |
9 | 78533166663108 |
10 | 20221100331983 |
11 | 64967a1a79a31 |
12 | 2326b997070bb |
13 | b38ac2c46645 |
14 | 4dc9c680c4b5 |
15 | 250ee5975608 |
hex | 1264178093cf |
20221100331983 has 2 divisors, whose sum is σ = 20221100331984. Its totient is φ = 20221100331982.
The previous prime is 20221100331973. The next prime is 20221100332231. The reversal of 20221100331983 is 38913300112202.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 20221100331983 - 216 = 20221100266447 is a prime.
It is a super-2 number, since 2×202211003319832 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (20221100331953) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10110550165991 + 10110550165992.
It is an arithmetic number, because the mean of its divisors is an integer number (10110550165992).
Almost surely, 220221100331983 is an apocalyptic number.
20221100331983 is a deficient number, since it is larger than the sum of its proper divisors (1).
20221100331983 is an equidigital number, since it uses as much as digits as its factorization.
20221100331983 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 15552, while the sum is 35.
The spelling of 20221100331983 in words is "twenty trillion, two hundred twenty-one billion, one hundred million, three hundred thirty-one thousand, nine hundred eighty-three".
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