Base | Representation |
---|---|
bin | 11101011011001111010… |
… | …001100010111001000101 |
3 | 21011022102110200112110111 |
4 | 131123033101202321011 |
5 | 231112241200042242 |
6 | 4144540120153021 |
7 | 266043552233332 |
oct | 35331721427105 |
9 | 7138373615414 |
10 | 2022112112197 |
11 | 70a633630a81 |
12 | 287a95308771 |
13 | 1188b86aac28 |
14 | 6dc29495989 |
15 | 378ee3a4817 |
hex | 1d6cf462e45 |
2022112112197 has 2 divisors, whose sum is σ = 2022112112198. Its totient is φ = 2022112112196.
The previous prime is 2022112112177. The next prime is 2022112112231. The reversal of 2022112112197 is 7912112112202.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1917230698881 + 104881413316 = 1384641^2 + 323854^2 .
It is a cyclic number.
It is not a de Polignac number, because 2022112112197 - 211 = 2022112110149 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2022112112177) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1011056056098 + 1011056056099.
It is an arithmetic number, because the mean of its divisors is an integer number (1011056056099).
Almost surely, 22022112112197 is an apocalyptic number.
It is an amenable number.
2022112112197 is a deficient number, since it is larger than the sum of its proper divisors (1).
2022112112197 is an equidigital number, since it uses as much as digits as its factorization.
2022112112197 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2016, while the sum is 31.
Adding to 2022112112197 its reverse (7912112112202), we get a palindrome (9934224224399).
The spelling of 2022112112197 in words is "two trillion, twenty-two billion, one hundred twelve million, one hundred twelve thousand, one hundred ninety-seven".
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