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20221311100121 is a prime number
BaseRepresentation
bin1001001100100001001000…
…00100001010010011011001
32122121010201221100020122122
410212100210010022103121
510122301221120200441
6111001313031031025
74154640640234055
oct446204404122331
978533657306578
1020221311100121
11649689aa4717a
12232703820b475
13b38b27801011
144dca067d4c65
1525100920a34b
hex12642410a4d9

20221311100121 has 2 divisors, whose sum is σ = 20221311100122. Its totient is φ = 20221311100120.

The previous prime is 20221311099949. The next prime is 20221311100129. The reversal of 20221311100121 is 12100111312202.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 19548601104400 + 672709995721 = 4421380^2 + 820189^2 .

It is a cyclic number.

It is not a de Polignac number, because 20221311100121 - 230 = 20220237358297 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 20221311100121.

It is not a weakly prime, because it can be changed into another prime (20221311100129) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10110655550060 + 10110655550061.

It is an arithmetic number, because the mean of its divisors is an integer number (10110655550061).

Almost surely, 220221311100121 is an apocalyptic number.

It is an amenable number.

20221311100121 is a deficient number, since it is larger than the sum of its proper divisors (1).

20221311100121 is an equidigital number, since it uses as much as digits as its factorization.

20221311100121 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 48, while the sum is 17.

Adding to 20221311100121 its reverse (12100111312202), we get a palindrome (32321422412323).

The spelling of 20221311100121 in words is "twenty trillion, two hundred twenty-one billion, three hundred eleven million, one hundred thousand, one hundred twenty-one".