20222011121131 has 2 divisors, whose sum is σ = 20222011121132. Its totient is φ = 20222011121130.

The previous prime is 20222011121111. The next prime is 20222011121149. The reversal of 20222011121131 is 13112111022202.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 20222011121131 - 2²³ = 20222002732523 is a prime.

It is a super-3 number, since 3×20222011121131³ (a number of 41 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a junction number, because it is equal to n+sod(n) for n = 20222011121099 and 20222011121108.

It is not a weakly prime, because it can be changed into another prime (20222011121111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10111005560565 + 10111005560566.

It is an arithmetic number, because the mean of its divisors is an integer number (10111005560566).

Almost surely, 2^{20222011121131} is an apocalyptic number.

20222011121131 is a deficient number, since it is larger than the sum of its proper divisors (1).

20222011121131 is an equidigital number, since it uses as much as digits as its factorization.

20222011121131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 96, while the sum is 19.

Adding to 20222011121131 its reverse (13112111022202), we get a palindrome (33334122143333).

The spelling of 20222011121131 in words is "twenty trillion, two hundred twenty-two billion, eleven million, one hundred twenty-one thousand, one hundred thirty-one".