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2022201112121 is a prime number
BaseRepresentation
bin11101011011010100100…
…101000011011000111001
321011022122200011012101222
4131123110211003120321
5231112431441041441
64144553015521425
7266046012562331
oct35332445033071
97138580135358
102022201112121
1170a679899a33
12287abb089275
13118900c6c8c8
146dc372220c1
15379070d4d4b
hex1d6d4943639

2022201112121 has 2 divisors, whose sum is σ = 2022201112122. Its totient is φ = 2022201112120.

The previous prime is 2022201112097. The next prime is 2022201112133. The reversal of 2022201112121 is 1212111022202.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1482211286521 + 539989825600 = 1217461^2 + 734840^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2022201112121 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 2022201112121.

It is not a weakly prime, because it can be changed into another prime (2022201118121) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1011100556060 + 1011100556061.

It is an arithmetic number, because the mean of its divisors is an integer number (1011100556061).

Almost surely, 22022201112121 is an apocalyptic number.

It is an amenable number.

2022201112121 is a deficient number, since it is larger than the sum of its proper divisors (1).

2022201112121 is an equidigital number, since it uses as much as digits as its factorization.

2022201112121 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 64, while the sum is 17.

Adding to 2022201112121 its reverse (1212111022202), we get a palindrome (3234312134323).

The spelling of 2022201112121 in words is "two trillion, twenty-two billion, two hundred one million, one hundred twelve thousand, one hundred twenty-one".