Base | Representation |
---|---|
bin | 1001001100100010011100… |
… | …11100011101000000010011 |
3 | 2122121012120111020100120012 |
4 | 10212101032130131000103 |
5 | 10122304200130030001 |
6 | 111001511350305135 |
7 | 4154664362565602 |
oct | 446211634350023 |
9 | 78535514210505 |
10 | 20222022111251 |
11 | 6497125327384 |
12 | 23271b63581ab |
13 | b38c0bbc726c |
14 | 4dca72dd7a39 |
15 | 25104b8552bb |
hex | 12644e71d013 |
20222022111251 has 2 divisors, whose sum is σ = 20222022111252. Its totient is φ = 20222022111250.
The previous prime is 20222022111223. The next prime is 20222022111253. The reversal of 20222022111251 is 15211122022202.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-20222022111251 is a prime.
Together with 20222022111253, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (20222022111253) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10111011055625 + 10111011055626.
It is an arithmetic number, because the mean of its divisors is an integer number (10111011055626).
Almost surely, 220222022111251 is an apocalyptic number.
20222022111251 is a deficient number, since it is larger than the sum of its proper divisors (1).
20222022111251 is an equidigital number, since it uses as much as digits as its factorization.
20222022111251 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 640, while the sum is 23.
Adding to 20222022111251 its reverse (15211122022202), we get a palindrome (35433144133453).
The spelling of 20222022111251 in words is "twenty trillion, two hundred twenty-two billion, twenty-two million, one hundred eleven thousand, two hundred fifty-one".
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