Base | Representation |
---|---|
bin | 11101011011011100111… |
… | …111000010000001000111 |
3 | 21011100000111112011020211 |
4 | 131123130333002001013 |
5 | 231113224041434400 |
6 | 4145015014340251 |
7 | 266052344363263 |
oct | 35333477020107 |
9 | 7140014464224 |
10 | 2022342139975 |
11 | 70a741463283 |
12 | 287b3a35a687 |
13 | 118924249a41 |
14 | 6dc4bc530a3 |
15 | 37914690dba |
hex | 1d6dcfc2047 |
2022342139975 has 48 divisors (see below), whose sum is σ = 2660058800896. Its totient is φ = 1522509696000.
The previous prime is 2022342139919. The next prime is 2022342140003. The reversal of 2022342139975 is 5799312432202.
It is not a de Polignac number, because 2022342139975 - 213 = 2022342131783 is a prime.
It is a super-3 number, since 3×20223421399753 (a number of 38 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 53345227 + ... + 53383123.
Almost surely, 22022342139975 is an apocalyptic number.
2022342139975 is a gapful number since it is divisible by the number (25) formed by its first and last digit.
2022342139975 is a deficient number, since it is larger than the sum of its proper divisors (637716660921).
2022342139975 is a wasteful number, since it uses less digits than its factorization.
2022342139975 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 39836 (or 39831 counting only the distinct ones).
The product of its (nonzero) digits is 1632960, while the sum is 49.
The spelling of 2022342139975 in words is "two trillion, twenty-two billion, three hundred forty-two million, one hundred thirty-nine thousand, nine hundred seventy-five".
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