Base | Representation |
---|---|
bin | 11101011100001010110… |
… | …100011101010101010101 |
3 | 21011102000002111101211101 |
4 | 131130022310131111111 |
5 | 231121312421321323 |
6 | 4145223204310101 |
7 | 266110402533211 |
oct | 35341264352525 |
9 | 7142002441741 |
10 | 2023111120213 |
11 | 70aaa6537537 |
12 | 2881139a2331 |
13 | 118a1765b731 |
14 | 6dcc2025941 |
15 | 3795be3bdad |
hex | 1d70ad1d555 |
2023111120213 has 2 divisors, whose sum is σ = 2023111120214. Its totient is φ = 2023111120212.
The previous prime is 2023111120201. The next prime is 2023111120243. The reversal of 2023111120213 is 3120211113202.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1856632431889 + 166478688324 = 1362583^2 + 408018^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2023111120213 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2023111120243) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1011555560106 + 1011555560107.
It is an arithmetic number, because the mean of its divisors is an integer number (1011555560107).
Almost surely, 22023111120213 is an apocalyptic number.
It is an amenable number.
2023111120213 is a deficient number, since it is larger than the sum of its proper divisors (1).
2023111120213 is an equidigital number, since it uses as much as digits as its factorization.
2023111120213 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 144, while the sum is 19.
Adding to 2023111120213 its reverse (3120211113202), we get a palindrome (5143322233415).
The spelling of 2023111120213 in words is "two trillion, twenty-three billion, one hundred eleven million, one hundred twenty thousand, two hundred thirteen".
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