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2023111120213 is a prime number
BaseRepresentation
bin11101011100001010110…
…100011101010101010101
321011102000002111101211101
4131130022310131111111
5231121312421321323
64145223204310101
7266110402533211
oct35341264352525
97142002441741
102023111120213
1170aaa6537537
122881139a2331
13118a1765b731
146dcc2025941
153795be3bdad
hex1d70ad1d555

2023111120213 has 2 divisors, whose sum is σ = 2023111120214. Its totient is φ = 2023111120212.

The previous prime is 2023111120201. The next prime is 2023111120243. The reversal of 2023111120213 is 3120211113202.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1856632431889 + 166478688324 = 1362583^2 + 408018^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2023111120213 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2023111120243) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1011555560106 + 1011555560107.

It is an arithmetic number, because the mean of its divisors is an integer number (1011555560107).

Almost surely, 22023111120213 is an apocalyptic number.

It is an amenable number.

2023111120213 is a deficient number, since it is larger than the sum of its proper divisors (1).

2023111120213 is an equidigital number, since it uses as much as digits as its factorization.

2023111120213 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 2023111120213 its reverse (3120211113202), we get a palindrome (5143322233415).

The spelling of 2023111120213 in words is "two trillion, twenty-three billion, one hundred eleven million, one hundred twenty thousand, two hundred thirteen".