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202311122103197 is a prime number
BaseRepresentation
bin101110000000000000111010…
…100100010010101110011101
3222112022202100221121022121122
4232000000322210102232131
5203004131134224300242
61554140240232540325
760420332130132122
oct5600007244225635
9875282327538548
10202311122103197
115950a735207158
121a8353015516a5
1388b6b1a95b7b3
1437d5ca67cc749
15185c89ad88ad2
hexb8003a912b9d

202311122103197 has 2 divisors, whose sum is σ = 202311122103198. Its totient is φ = 202311122103196.

The previous prime is 202311122103133. The next prime is 202311122103257. The reversal of 202311122103197 is 791301221113202.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 190277029280836 + 12034092822361 = 13794094^2 + 3469019^2 .

It is a cyclic number.

It is not a de Polignac number, because 202311122103197 - 26 = 202311122103133 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (202311122103397) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 101155561051598 + 101155561051599.

It is an arithmetic number, because the mean of its divisors is an integer number (101155561051599).

Almost surely, 2202311122103197 is an apocalyptic number.

It is an amenable number.

202311122103197 is a deficient number, since it is larger than the sum of its proper divisors (1).

202311122103197 is an equidigital number, since it uses as much as digits as its factorization.

202311122103197 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 9072, while the sum is 35.

Adding to 202311122103197 its reverse (791301221113202), we get a palindrome (993612343216399).

The spelling of 202311122103197 in words is "two hundred two trillion, three hundred eleven billion, one hundred twenty-two million, one hundred three thousand, one hundred ninety-seven".