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2023122120223 is a prime number
BaseRepresentation
bin11101011100001011011…
…110011010111000011111
321011102000212012021000011
4131130023132122320133
5231121323230321343
64145224240144051
7266110565166211
oct35341336327037
97142025167004
102023122120223
1171000176aa56
12288117608027
13118a19a10509
146dcc368a5b1
153795cdb129d
hex1d70b79ae1f

2023122120223 has 2 divisors, whose sum is σ = 2023122120224. Its totient is φ = 2023122120222.

The previous prime is 2023122120167. The next prime is 2023122120259. The reversal of 2023122120223 is 3220212213202.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 2023122120223 - 217 = 2023121989151 is a prime.

It is a super-2 number, since 2×20231221202232 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 2023122120194 and 2023122120203.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2023122120823) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1011561060111 + 1011561060112.

It is an arithmetic number, because the mean of its divisors is an integer number (1011561060112).

Almost surely, 22023122120223 is an apocalyptic number.

2023122120223 is a deficient number, since it is larger than the sum of its proper divisors (1).

2023122120223 is an equidigital number, since it uses as much as digits as its factorization.

2023122120223 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1152, while the sum is 22.

Adding to 2023122120223 its reverse (3220212213202), we get a palindrome (5243334333425).

The spelling of 2023122120223 in words is "two trillion, twenty-three billion, one hundred twenty-two million, one hundred twenty thousand, two hundred twenty-three".