Base | Representation |
---|---|
bin | 1001001100110011110111… |
… | …01001100111011011010111 |
3 | 2122122002200222211020111011 |
4 | 10212121323221213123113 |
5 | 10122432321320034002 |
6 | 111010055134153051 |
7 | 4155445135413244 |
oct | 446317351473327 |
9 | 78562628736434 |
10 | 20231370471127 |
11 | 64a0092222532 |
12 | 2328b85052787 |
13 | b39a6b8a805a |
14 | 4dd2bc7b05cb |
15 | 2513e73e48d7 |
hex | 12667ba676d7 |
20231370471127 has 2 divisors, whose sum is σ = 20231370471128. Its totient is φ = 20231370471126.
The previous prime is 20231370471113. The next prime is 20231370471157. The reversal of 20231370471127 is 72117407313202.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-20231370471127 is a prime.
It is a super-2 number, since 2×202313704711272 (a number of 27 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 20231370471127.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (20231370471107) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10115685235563 + 10115685235564.
It is an arithmetic number, because the mean of its divisors is an integer number (10115685235564).
Almost surely, 220231370471127 is an apocalyptic number.
20231370471127 is a deficient number, since it is larger than the sum of its proper divisors (1).
20231370471127 is an equidigital number, since it uses as much as digits as its factorization.
20231370471127 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 98784, while the sum is 40.
Adding to 20231370471127 its reverse (72117407313202), we get a palindrome (92348777784329).
The spelling of 20231370471127 in words is "twenty trillion, two hundred thirty-one billion, three hundred seventy million, four hundred seventy-one thousand, one hundred twenty-seven".
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