Base | Representation |
---|---|
bin | 11101011100010000010… |
… | …011011101101010110011 |
3 | 21011102020111122012012021 |
4 | 131130100103131222303 |
5 | 231122010000243011 |
6 | 4145240252412311 |
7 | 266112600614314 |
oct | 35342023355263 |
9 | 7142214565167 |
10 | 2023203134131 |
11 | 7100434739a3 |
12 | 28813a777097 |
13 | 118a3073723a |
14 | 6dcd033860b |
15 | 37965065471 |
hex | 1d7104ddab3 |
2023203134131 has 2 divisors, whose sum is σ = 2023203134132. Its totient is φ = 2023203134130.
The previous prime is 2023203134083. The next prime is 2023203134137. The reversal of 2023203134131 is 1314313023202.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2023203134131 - 29 = 2023203133619 is a prime.
It is a super-2 number, since 2×20232031341312 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 2023203134096 and 2023203134105.
It is not a weakly prime, because it can be changed into another prime (2023203134137) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1011601567065 + 1011601567066.
It is an arithmetic number, because the mean of its divisors is an integer number (1011601567066).
Almost surely, 22023203134131 is an apocalyptic number.
2023203134131 is a deficient number, since it is larger than the sum of its proper divisors (1).
2023203134131 is an equidigital number, since it uses as much as digits as its factorization.
2023203134131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2592, while the sum is 25.
Adding to 2023203134131 its reverse (1314313023202), we get a palindrome (3337516157333).
The spelling of 2023203134131 in words is "two trillion, twenty-three billion, two hundred three million, one hundred thirty-four thousand, one hundred thirty-one".
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