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2023210441237 is a prime number
BaseRepresentation
bin11101011100010000101…
…111010101101000010101
321011102021000101102122211
4131130100233111220111
5231122013333104422
64145241113153421
7266113016666656
oct35342057255025
97142230342584
102023210441237
11710047604927
122881410bb871
13118a320c517b
146dcd12bb52d
1537965a0a577
hex1d710bd5a15

2023210441237 has 2 divisors, whose sum is σ = 2023210441238. Its totient is φ = 2023210441236.

The previous prime is 2023210441157. The next prime is 2023210441253. The reversal of 2023210441237 is 7321440123202.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1538180374756 + 485030066481 = 1240234^2 + 696441^2 .

It is a cyclic number.

It is not a de Polignac number, because 2023210441237 - 223 = 2023202052629 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 2023210441199 and 2023210441208.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2023210441277) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1011605220618 + 1011605220619.

It is an arithmetic number, because the mean of its divisors is an integer number (1011605220619).

Almost surely, 22023210441237 is an apocalyptic number.

It is an amenable number.

2023210441237 is a deficient number, since it is larger than the sum of its proper divisors (1).

2023210441237 is an equidigital number, since it uses as much as digits as its factorization.

2023210441237 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 16128, while the sum is 31.

Adding to 2023210441237 its reverse (7321440123202), we get a palindrome (9344650564439).

The spelling of 2023210441237 in words is "two trillion, twenty-three billion, two hundred ten million, four hundred forty-one thousand, two hundred thirty-seven".