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20233201121953 is a prime number
BaseRepresentation
bin1001001100110111010001…
…10000111111101010100001
32122122021102120111221022121
410212123220300333222201
510123000043441400303
6111011000531304241
74155541404606541
oct446335060775241
978567376457277
1020233201121953
1164a09416115a6
1223293b614b081
13b39ca0c3a3b1
144dd413985321
152514a2ea49bd
hex1266e8c3faa1

20233201121953 has 2 divisors, whose sum is σ = 20233201121954. Its totient is φ = 20233201121952.

The previous prime is 20233201121911. The next prime is 20233201122103. The reversal of 20233201121953 is 35912110233202.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 19575598522624 + 657602599329 = 4424432^2 + 810927^2 .

It is a cyclic number.

It is not a de Polignac number, because 20233201121953 - 213 = 20233201113761 is a prime.

It is a super-3 number, since 3×202332011219533 (a number of 41 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (20233201121153) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10116600560976 + 10116600560977.

It is an arithmetic number, because the mean of its divisors is an integer number (10116600560977).

Almost surely, 220233201121953 is an apocalyptic number.

It is an amenable number.

20233201121953 is a deficient number, since it is larger than the sum of its proper divisors (1).

20233201121953 is an equidigital number, since it uses as much as digits as its factorization.

20233201121953 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 19440, while the sum is 34.

The spelling of 20233201121953 in words is "twenty trillion, two hundred thirty-three billion, two hundred one million, one hundred twenty-one thousand, nine hundred fifty-three".