Base | Representation |
---|---|
bin | 11101011100011100111… |
… | …001011101001110111011 |
3 | 21011102210020012122111001 |
4 | 131130130321131032323 |
5 | 231122423042423121 |
6 | 4145313241145431 |
7 | 266121044536306 |
oct | 35343471351673 |
9 | 7142706178431 |
10 | 2023414420411 |
11 | 71014176545a |
12 | 28819948b277 |
13 | 118a654436c7 |
14 | 6dd10417b3d |
15 | 3797889d991 |
hex | 1d71ce5d3bb |
2023414420411 has 2 divisors, whose sum is σ = 2023414420412. Its totient is φ = 2023414420410.
The previous prime is 2023414420393. The next prime is 2023414420429. The reversal of 2023414420411 is 1140244143202.
It is a balanced prime because it is at equal distance from previous prime (2023414420393) and next prime (2023414420429).
It is a cyclic number.
It is not a de Polignac number, because 2023414420411 - 217 = 2023414289339 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 2023414420411.
It is not a weakly prime, because it can be changed into another prime (2023414420481) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1011707210205 + 1011707210206.
It is an arithmetic number, because the mean of its divisors is an integer number (1011707210206).
Almost surely, 22023414420411 is an apocalyptic number.
2023414420411 is a deficient number, since it is larger than the sum of its proper divisors (1).
2023414420411 is an equidigital number, since it uses as much as digits as its factorization.
2023414420411 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6144, while the sum is 28.
Adding to 2023414420411 its reverse (1140244143202), we get a palindrome (3163658563613).
The spelling of 2023414420411 in words is "two trillion, twenty-three billion, four hundred fourteen million, four hundred twenty thousand, four hundred eleven".
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