Search a number
-
+
2023443101041 is a prime number
BaseRepresentation
bin11101011100011110100…
…110110111010101110001
321011102212020011202220121
4131130132212313111301
5231123002413213131
64145320144010241
7266121543401305
oct35343646672561
97142766152817
102023443101041
1171015697465a
122881a7000981
13118a6b375cab
146dd14161d05
153797b166911
hex1d71e9b7571

2023443101041 has 2 divisors, whose sum is σ = 2023443101042. Its totient is φ = 2023443101040.

The previous prime is 2023443101027. The next prime is 2023443101051. The reversal of 2023443101041 is 1401013443202.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1924104668641 + 99338432400 = 1387121^2 + 315180^2 .

It is a cyclic number.

It is not a de Polignac number, because 2023443101041 - 213 = 2023443092849 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 2023443100997 and 2023443101015.

It is not a weakly prime, because it can be changed into another prime (2023443101051) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1011721550520 + 1011721550521.

It is an arithmetic number, because the mean of its divisors is an integer number (1011721550521).

Almost surely, 22023443101041 is an apocalyptic number.

It is an amenable number.

2023443101041 is a deficient number, since it is larger than the sum of its proper divisors (1).

2023443101041 is an equidigital number, since it uses as much as digits as its factorization.

2023443101041 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 2023443101041 its reverse (1401013443202), we get a palindrome (3424456544243).

The spelling of 2023443101041 in words is "two trillion, twenty-three billion, four hundred forty-three million, one hundred one thousand, forty-one".