Base | Representation |
---|---|
bin | 1001001101011000100110… |
… | …00100001101111100100111 |
3 | 2122200222121022212022110212 |
4 | 10212230103010031330213 |
5 | 10123243213203022242 |
6 | 111023120030410035 |
7 | 4160043622361414 |
oct | 446542304157447 |
9 | 78628538768425 |
10 | 20251090673447 |
11 | 64a84918163a7 |
12 | 233096936091b |
13 | b3b89230941a |
14 | 50022d86110b |
15 | 251b9d7e2782 |
hex | 126b1310df27 |
20251090673447 has 2 divisors, whose sum is σ = 20251090673448. Its totient is φ = 20251090673446.
The previous prime is 20251090673417. The next prime is 20251090673461. The reversal of 20251090673447 is 74437609015202.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 20251090673447 - 212 = 20251090669351 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 20251090673395 and 20251090673404.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (20251090673417) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10125545336723 + 10125545336724.
It is an arithmetic number, because the mean of its divisors is an integer number (10125545336724).
Almost surely, 220251090673447 is an apocalyptic number.
20251090673447 is a deficient number, since it is larger than the sum of its proper divisors (1).
20251090673447 is an equidigital number, since it uses as much as digits as its factorization.
20251090673447 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2540160, while the sum is 50.
Adding to 20251090673447 its reverse (74437609015202), we get a palindrome (94688699688649).
The spelling of 20251090673447 in words is "twenty trillion, two hundred fifty-one billion, ninety million, six hundred seventy-three thousand, four hundred forty-seven".
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