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20251090673447 is a prime number
BaseRepresentation
bin1001001101011000100110…
…00100001101111100100111
32122200222121022212022110212
410212230103010031330213
510123243213203022242
6111023120030410035
74160043622361414
oct446542304157447
978628538768425
1020251090673447
1164a84918163a7
12233096936091b
13b3b89230941a
1450022d86110b
15251b9d7e2782
hex126b1310df27

20251090673447 has 2 divisors, whose sum is σ = 20251090673448. Its totient is φ = 20251090673446.

The previous prime is 20251090673417. The next prime is 20251090673461. The reversal of 20251090673447 is 74437609015202.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 20251090673447 - 212 = 20251090669351 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 20251090673395 and 20251090673404.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (20251090673417) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10125545336723 + 10125545336724.

It is an arithmetic number, because the mean of its divisors is an integer number (10125545336724).

Almost surely, 220251090673447 is an apocalyptic number.

20251090673447 is a deficient number, since it is larger than the sum of its proper divisors (1).

20251090673447 is an equidigital number, since it uses as much as digits as its factorization.

20251090673447 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2540160, while the sum is 50.

Adding to 20251090673447 its reverse (74437609015202), we get a palindrome (94688699688649).

The spelling of 20251090673447 in words is "twenty trillion, two hundred fifty-one billion, ninety million, six hundred seventy-three thousand, four hundred forty-seven".