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20251141510673 is a prime number
BaseRepresentation
bin1001001101011000101100…
…00110001001011000010001
32122200222201212112010001002
410212230112012021120101
510123243314211320143
6111023125044151345
74160045110444043
oct446542606113021
978628655463032
1020251141510673
1164a8508489137
122330982398555
13b3b89c9c8918
145002364d5a93
15251ba2ed55b8
hex126b16189611

20251141510673 has 2 divisors, whose sum is σ = 20251141510674. Its totient is φ = 20251141510672.

The previous prime is 20251141510597. The next prime is 20251141510693. The reversal of 20251141510673 is 37601514115202.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 14907683936209 + 5343457574464 = 3861047^2 + 2311592^2 .

It is a cyclic number.

It is not a de Polignac number, because 20251141510673 - 212 = 20251141506577 is a prime.

It is not a weakly prime, because it can be changed into another prime (20251141510693) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10125570755336 + 10125570755337.

It is an arithmetic number, because the mean of its divisors is an integer number (10125570755337).

Almost surely, 220251141510673 is an apocalyptic number.

It is an amenable number.

20251141510673 is a deficient number, since it is larger than the sum of its proper divisors (1).

20251141510673 is an equidigital number, since it uses as much as digits as its factorization.

20251141510673 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 50400, while the sum is 38.

Adding to 20251141510673 its reverse (37601514115202), we get a palindrome (57852655625875).

The spelling of 20251141510673 in words is "twenty trillion, two hundred fifty-one billion, one hundred forty-one million, five hundred ten thousand, six hundred seventy-three".