Base | Representation |
---|---|
bin | 1001001101011000101100… |
… | …00110001001011000010001 |
3 | 2122200222201212112010001002 |
4 | 10212230112012021120101 |
5 | 10123243314211320143 |
6 | 111023125044151345 |
7 | 4160045110444043 |
oct | 446542606113021 |
9 | 78628655463032 |
10 | 20251141510673 |
11 | 64a8508489137 |
12 | 2330982398555 |
13 | b3b89c9c8918 |
14 | 5002364d5a93 |
15 | 251ba2ed55b8 |
hex | 126b16189611 |
20251141510673 has 2 divisors, whose sum is σ = 20251141510674. Its totient is φ = 20251141510672.
The previous prime is 20251141510597. The next prime is 20251141510693. The reversal of 20251141510673 is 37601514115202.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 14907683936209 + 5343457574464 = 3861047^2 + 2311592^2 .
It is a cyclic number.
It is not a de Polignac number, because 20251141510673 - 212 = 20251141506577 is a prime.
It is not a weakly prime, because it can be changed into another prime (20251141510693) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10125570755336 + 10125570755337.
It is an arithmetic number, because the mean of its divisors is an integer number (10125570755337).
Almost surely, 220251141510673 is an apocalyptic number.
It is an amenable number.
20251141510673 is a deficient number, since it is larger than the sum of its proper divisors (1).
20251141510673 is an equidigital number, since it uses as much as digits as its factorization.
20251141510673 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 50400, while the sum is 38.
Adding to 20251141510673 its reverse (37601514115202), we get a palindrome (57852655625875).
The spelling of 20251141510673 in words is "twenty trillion, two hundred fifty-one billion, one hundred forty-one million, five hundred ten thousand, six hundred seventy-three".
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