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2025254113 is a prime number
BaseRepresentation
bin111100010110110…
…1110110011100001
312020010212120100121
41320231232303201
513121431112423
6532544120241
7101121242641
oct17055566341
95203776317
102025254113
1194a226433
12486306081
1326377a11c
14152d90521
15bcc0045d
hex78b6ece1

2025254113 has 2 divisors, whose sum is σ = 2025254114. Its totient is φ = 2025254112.

The previous prime is 2025254093. The next prime is 2025254131. The reversal of 2025254113 is 3114525202.

Together with next prime (2025254131) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1825681984 + 199572129 = 42728^2 + 14127^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2025254113 is a prime.

It is not a weakly prime, because it can be changed into another prime (2025254713) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1012627056 + 1012627057.

It is an arithmetic number, because the mean of its divisors is an integer number (1012627057).

Almost surely, 22025254113 is an apocalyptic number.

It is an amenable number.

2025254113 is a deficient number, since it is larger than the sum of its proper divisors (1).

2025254113 is an equidigital number, since it uses as much as digits as its factorization.

2025254113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2400, while the sum is 25.

The square root of 2025254113 is about 45002.8233892053. The cubic root of 2025254113 is about 1265.2019160367.

Adding to 2025254113 its reverse (3114525202), we get a palindrome (5139779315).

The spelling of 2025254113 in words is "two billion, twenty-five million, two hundred fifty-four thousand, one hundred thirteen".