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2030100000311 is a prime number
BaseRepresentation
bin11101100010101011011…
…000111010111000110111
321012002001011022021222102
4131202223120322320313
5231230121100002221
64152340504252315
7266445525200015
oct35425330727067
97162034267872
102030100000311
11712a625865a9
1228954447109b
1311958c570146
14703862c98b5
1537c1a7ab30b
hex1d8ab63ae37

2030100000311 has 2 divisors, whose sum is σ = 2030100000312. Its totient is φ = 2030100000310.

The previous prime is 2030100000209. The next prime is 2030100000337. The reversal of 2030100000311 is 1130000010302.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 2030100000311 - 214 = 2030099983927 is a prime.

It is a super-2 number, since 2×20301000003112 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 2030100000292 and 2030100000301.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2030100002311) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1015050000155 + 1015050000156.

It is an arithmetic number, because the mean of its divisors is an integer number (1015050000156).

Almost surely, 22030100000311 is an apocalyptic number.

2030100000311 is a deficient number, since it is larger than the sum of its proper divisors (1).

2030100000311 is an equidigital number, since it uses as much as digits as its factorization.

2030100000311 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 18, while the sum is 11.

Adding to 2030100000311 its reverse (1130000010302), we get a palindrome (3160100010613).

Subtracting from 2030100000311 its reverse (1130000010302), we obtain a palindrome (900099990009).

The spelling of 2030100000311 in words is "two trillion, thirty billion, one hundred million, three hundred eleven", and thus it is an aban number.