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2030110211 is a prime number
BaseRepresentation
bin111100100000001…
…0000011000000011
312020111000021200002
41321000100120003
513124202011321
6533240150215
7101210436443
oct17100203003
95214007602
102030110211
11951a42938
12487a6836b
1326478a55c
14153896123
15bd35e20b
hex79010603

2030110211 has 2 divisors, whose sum is σ = 2030110212. Its totient is φ = 2030110210.

The previous prime is 2030110207. The next prime is 2030110213. The reversal of 2030110211 is 1120110302.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 2030110211 - 22 = 2030110207 is a prime.

Together with 2030110213, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 2030110192 and 2030110201.

It is not a weakly prime, because it can be changed into another prime (2030110213) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1015055105 + 1015055106.

It is an arithmetic number, because the mean of its divisors is an integer number (1015055106).

Almost surely, 22030110211 is an apocalyptic number.

2030110211 is a deficient number, since it is larger than the sum of its proper divisors (1).

2030110211 is an equidigital number, since it uses as much as digits as its factorization.

2030110211 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 12, while the sum is 11.

The square root of 2030110211 is about 45056.7443453253. The cubic root of 2030110211 is about 1266.2123308767.

Adding to 2030110211 its reverse (1120110302), we get a palindrome (3150220513).

Subtracting from 2030110211 its reverse (1120110302), we obtain a palindrome (909999909).

The spelling of 2030110211 in words is "two billion, thirty million, one hundred ten thousand, two hundred eleven".