Base | Representation |
---|---|
bin | 101110001011101011110101… |
… | …011000101000000010110001 |
3 | 222122011102110120201000222221 |
4 | 232023223311120220002301 |
5 | 203110301132244114413 |
6 | 1555552513533401041 |
7 | 60532303316262322 |
oct | 5613536530500261 |
9 | 878142416630887 |
10 | 203113120301233 |
11 | 5979987729768a |
12 | 1a944825039181 |
13 | 894463c8a126c |
14 | 3822a282a0449 |
15 | 18736897d468d |
hex | b8baf56280b1 |
203113120301233 has 2 divisors, whose sum is σ = 203113120301234. Its totient is φ = 203113120301232.
The previous prime is 203113120301207. The next prime is 203113120301251. The reversal of 203113120301233 is 332103021311302.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 172941752135824 + 30171368165409 = 13150732^2 + 5492847^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-203113120301233 is a prime.
It is a super-2 number, since 2×2031131203012332 (a number of 29 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 203113120301198 and 203113120301207.
It is not a weakly prime, because it can be changed into another prime (203113120301263) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 101556560150616 + 101556560150617.
It is an arithmetic number, because the mean of its divisors is an integer number (101556560150617).
Almost surely, 2203113120301233 is an apocalyptic number.
It is an amenable number.
203113120301233 is a deficient number, since it is larger than the sum of its proper divisors (1).
203113120301233 is an equidigital number, since it uses as much as digits as its factorization.
203113120301233 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1944, while the sum is 25.
Adding to 203113120301233 its reverse (332103021311302), we get a palindrome (535216141612535).
The spelling of 203113120301233 in words is "two hundred three trillion, one hundred thirteen billion, one hundred twenty million, three hundred one thousand, two hundred thirty-three".
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