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203121210000001 is a prime number
BaseRepresentation
bin101110001011110011010111…
…100100011000001010000001
3222122012012100100220022110211
4232023303113210120022001
5203110414214230000001
62000000332355554121
760533010636502036
oct5613632744301201
9878165310808424
10203121210000001
11597a2248760047
121a9463022bb941
13894532b88c177
14382319483738d
1518739aeaec351
hexb8bcd7918281

203121210000001 has 2 divisors, whose sum is σ = 203121210000002. Its totient is φ = 203121210000000.

The previous prime is 203121209999989. The next prime is 203121210000043. The reversal of 203121210000001 is 100000012121302.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 171549116600976 + 31572093399025 = 13097676^2 + 5618905^2 .

It is a cyclic number.

It is not a de Polignac number, because 203121210000001 - 25 = 203121209999969 is a prime.

It is a super-3 number, since 3×2031212100000013 (a number of 44 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (203121210000701) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 101560605000000 + 101560605000001.

It is an arithmetic number, because the mean of its divisors is an integer number (101560605000001).

Almost surely, 2203121210000001 is an apocalyptic number.

It is an amenable number.

203121210000001 is a deficient number, since it is larger than the sum of its proper divisors (1).

203121210000001 is an equidigital number, since it uses as much as digits as its factorization.

203121210000001 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 24, while the sum is 13.

Adding to 203121210000001 its reverse (100000012121302), we get a palindrome (303121222121303).

The spelling of 203121210000001 in words is "two hundred three trillion, one hundred twenty-one billion, two hundred ten million, one", and thus it is an aban number.